In this video, Cathy goes through four example ABG Interpretation problems and answers. You can download the questions and answers below to print out and follow along. We've also explained the steps for interpretation below.
Need help interpreting ABGs? Check out our Arterial Blood Gas Interpretation Flashcards for Nursing Students.
ABG practice question 5
A patient's arterial blood gas measurements read pH = 7.48, PaCO₂ = 31 mmHg, and HCO₃ = 20 mEq/L. How would you interpret this?
Steps for interpretation
- Check the pH to determine if we have acidosis or alkalosis. The normal range for pH is 7.35 - 7.45.
- The pH here is 7.48, which is out of range on the alkalotic side. Therefore, we have ALKALOSIS.
- Determine which system, metabolic or respiratory, is causing the alkalosis. Check the PaCO₂, which represents the respiratory system, first. The normal range for PaCO₂ is 35 - 45 mmHg.
- The PaCO₂ here is 31 mmHg, which is out of range on the alkalotic side, which is in the same direction as pH.
- Since the PaCO₂ is in the same direction as pH we know it is the respiratory system causing it.
- Therefore, the respiratory system is causing the alkalosis and we have RESPIRATORY ALKALOSIS.
- Check if there is compensation. Because it's respiratory alkalosis, it's the metabolic system that would be compensating. The metabolic system is represented by HCO₃. So we'll check HCO₃ to check for compensation. The normal range for HCO₃ is 22 - 26 mEq/L.
- The HCO₃ here is 20 mEq/L, which is out of range on the acidic side. This means there is metabolic compensation.
- To determine if the compensation is partial or full, we check the pH again. The pH was 7.48 which is out of range on the alkalotic side, so the metabolic system has not succeeded in fully compensating.
- Therefore, we have PARTIALLY COMPENSATED RESPIRATORY ALKALOSIS.
Lab Values & ABG Interpretation - Nursing Flashcards
ABG practice question 6
A patient's arterial blood gas measurements read pH = 7.45, PaCO₂ = 30 mmHg, and HCO₃ = 19 mEq/L. How would you interpret this?
Steps for interpretation
- Check the pH to determine if we have acidosis or alkalosis. The normal range for pH is 7.35 - 7.45.
- The pH here is 7.45, which is normal but on the alkalotic side. Therefore, we have ALKALOSIS.
- Determine which system, metabolic or respiratory, is causing the alkalosis. Check the PaCO₂, which represents the respiratory system, first. The normal range for PaCO₂ is 35 - 45 mmHg.
- The PaCO₂ here is 30 mmHg, which is out of range on the alkalotic side, which is in the same direction as pH.
- Since the PaCO₂ is in the same direction as pH we know it is the respiratory system causing it.
- Therefore, the respiratory system is causing the alkalosis and we have RESPIRATORY ALKALOSIS.
- Check if there is compensation. Because it's respiratory alkalosis, it's the metabolic system that would be compensating. The metabolic system is represented by HCO₃. So we'll check HCO₃ to check for compensation. The normal range for HCO₃ is 22 - 26 mEq/L.
- The HCO₃ here is 19 mEq/L, which is out of range on the acidic side. This means there is metabolic compensation.
- To determine if the compensation is partial or full, we check the pH again. The pH was 7.45 which is normal but on the alkalotic side, so the metabolic system has succeeded in fully compensating.
- Therefore, we have FULLY COMPENSATED RESPIRATORY ALKALOSIS.
ABG practice question 7
A patient's arterial blood gas measurements read pH = 7.32, PaCO₂ = 40 mmHg, and HCO₃ = 16 mEq/L. How would you interpret this?
Steps for interpretation
- Check the pH to determine if we have acidosis or alkalosis. The normal range for pH is 7.35 - 7.45.
- The pH here is 7.32, which is out of range on the acidic side. Therefore, we have ACIDOSIS.
- Determine which system, metabolic or respiratory, is causing the acidosis. Check the PaCO₂, which represents the respiratory system, first. The normal range for PaCO₂ is 35 - 45 mmHg.
- The PaCO₂ here is 40 mmHg, which is normal.
- Since the PaCO₂ is normal, we know it is not the respiratory system causing it.
- Therefore, the metabolic system is causing the acidosis and we have METABOLIC ACIDOSIS.
- Check if there is compensation. Because it's metabolic acidosis, it's the respiratory system that would be compensating. The respiratory system is represented by PaCO₂. So we'll check PaCO₂ again to check for compensation. The normal range for PaCO₂ is 35 - 45 mmHg.
- The PaCO₂ here is 40 mmHg, which, again, is within the normal range. This means there is no compensation.
- Therefore, we have UNCOMPENSATED METABOLIC ACIDOSIS.
ABG practice question 8
A patient's arterial blood gas measurements read pH = 7.31, PaCO₂ = 30 mmHg, and HCO₃ = 18 mEq/L. How would you interpret this?
Steps for interpretation
- Check the pH to determine if we have acidosis or alkalosis. The normal range for pH is 7.35 - 7.45.
- The pH here is 7.31, which is out of range on the acidic side. Therefore, we have ACIDOSIS.
- Determine which system, metabolic or respiratory, is causing the acidosis. Check the PaCO₂, which represents the respiratory system, first. The normal range for PaCO₂ is 35 - 45 mmHg.
- The PaCO₂ here is 30 mmHg, which is out of range on the alkalotic side , which is in the opposite direction as pH.
- Since the PaCO₂ is opposite direction as pH , we know it is not the respiratory system causing it.
- Therefore, the metabolic system is causing the acidosis and we have METABOLIC ACIDOSIS.
- Check if there is compensation. Because it's metabolic acidosis, it's the respiratory system that would be compensating. The respiratory system is represented by PaCO₂. So we'll check PaCO₂ again to check for compensation. The normal range for PaCO₂ is 35 - 45 mmHg.
- Remember the PaCO₂ here is 30 mmHg, which is out of range on the alkalotic side. This means there is respiratory compensation.
- To determine if the compensation is partial or full, we check the pH again. The pH was 7.31 which is out of range on the acidic side, so the respiratory system has not succeeded in fully compensating.
- Therefore, we have PARTIALLY COMPENSATED METABOLIC ACIDOSIS.
1 comment
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